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zvonat [6]
4 years ago
15

The perimeter of a college athletic field is 96 meters and the length is 12m more than the width. Find the width and length?

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
8 0
We are asked to define the width and length of a rectangular college athletic field with a parameter of 98 and length 12 more than the width, we represent x as the width, that is the length is x+12. Using parameter formula: 96/2 = x  + x+ 12 ; <span>48 = 2x + 12; x is equal to 18 m while x + 12 is equal to 30 m </span>
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3 years ago
Please explain how to do this
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Finding the percentage:

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=39.27

<u>subtract</u><u> </u><u>100</u><u>%</u><u> </u><u>by</u><u> </u><u>39.27</u><u>%</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>percentage</u><u> </u><u>of</u><u> </u><u>how</u><u> </u><u>much</u><u> </u><u>is</u><u> </u><u>shaded</u>

<u>=</u><u>100-39.27</u>

=60.73

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3 years ago
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