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4 years ago

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Candice enjoys eating foods high in vitamin C to stay healthy. On Saturday, she ate 4 clementines and 7 kiwis for a total of 732

mg of vitamin C. On Sunday, she ate 8 clementines and 5 kiwis for a total of 708 mg of vitamin C. How much vitamin C is in each fruit?

1 answer:

Alla [95]4 years ago

8 0

4c + 7k = 732
8c + 5k = 708

-8c - 14k = -1464
8c + 5k =. 708

-9k = -756

k= 84 mg of vitamin C in kiwis each

4c + 7(84)= 732

4c + 252 = 732

4c = 480

c = 120 mg of vitamin C in clementines each

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Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0

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The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

Step-by-step explanation:

The given is,

$2x+2y+z=- 2$ .......................................(1)

$-x-2y+2z=-5$ ......................................(2)

$2x+4y+z=0$ .........................................(3)

Step:1

Equation (2) is multiplied by -1 ( Eqn(2) × -1 )

$x+2y-2z=5$ .............................(4)

Subtract the equation (1) and (4)

$2x+2y+z=- 2$

$x+2y-2z=5$

( - )

$(2x-x)+(2y-2y)+(z+2z)=(-2-5)$

$x+3z=-7$ ......................(5)

Step:2

Equation (2) is multiplied by -2 ( Eqn(2) × -2)

$2x+4y-4z=10$ ........................(6)

Subtract equation (6) and (3),

$2x+4y-4z=10$

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$x+(3)(-2)=-7$

$x = -7+6$

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From equation (1),

$2x+2y+z=- 2$

Substitute x and z values,

$(2)(-1)+2y+(-2)=-2$

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$2y=4-2$

$2y=2$

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Step:3

Check for solution,

$-x-2y+2z=-5$

Substitute x,y and z values,

$-(-1)-(2)(1)+(2)(-2)=-5$

$1-2-4=-5$

-5 = -5

Result:

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

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<em />

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