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MissTica
3 years ago
7

1/6 of a dash if 2 more dash was add what would the answer be

Mathematics
1 answer:
Rama09 [41]3 years ago
4 0
2 and 1\6 dashes , add 2
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its 18

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What is equivalent to (3 root 8^1/4 x) ?
vfiekz [6]

Answer:

The given expression is equivalent to 3(2^(3/8))x.

Step-by-step explanation:

The given expression (3 root 8^1/4 x) can be written as:

3√(8^(1/4))x

we know that 2^3 = 8

= 3√(2^(3/4))x

We know that √x = (x)^(1/2)

= 3(2^((3/4)(1/2))x

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= 3(2^(3/8))x

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Maree is setting out snacks for friends she is having over. She has 18 crackers and 9 slices of cheese. If she wants each plate
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Answer: C. 9

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3 years ago
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A factory can produce two products,x and y, with a profit approximated by P=14x+22y-900. The production of y must exceed the pro
34kurt

Answers:

a) vertices: (400, 500); (0, 100); (1400,0)

b) production levels that yield the maximum profit and maximum profit:

x = 1400, y = 0, P = 18,700.

Explanation

Part A.

1) State the restrictions:

i) The production of y must exceed the production of x by at least 100 units:

⇒ y ≥ x + 100

ii) Production levels are limited by the formula x+2y ≤ 1400.

⇒ y ≤ 700 - x/2

iii) x and y cannot be negative:

⇒ x ≥ 0 and y ≥ 0

2) The feasible region is the area inside the lines defined by:

y = x + 100, y = 700 - x/2, y = 0, and x = 0

3) The vertices are found by solving 3 separated systems of equations:

i) intersection of lines y = x + 100 and y = 700 - x/2

⇒ x + 100 = 700 - x/2

⇒ 3x/2 = 600 ⇒ x= 1200 / 3 = 400

⇒ y = 400 + 100 = 500

⇒ vertex = (400, 500)

ii) intersection of lines y = x + 100 and x = 0

⇒ x = 0 and y = 100

⇒ vertex = (0, 100)

iii) intersection of lines y = 700 - x/2 and y = 0

⇒ y = 0 ⇒ x/2 = 700 ⇒ x = 1400

⇒ vertex = (1400, 0)

Therefore the vertices of the feasible region are:

(400, 500); (0, 100); (1400,0)

Part B.

The production levels that yield the maximum profit, and the maximum profit are found by replacing the vertices in the profit equation. The vertex that yields the maximum profit is the solution

1) vertex (400, 500)

P = 14x + 22y - 900 = 14(400) + 22(500) - 900 = 15,700

2) vertex (0, 100)

P = 14x + 22y - 900 = 14(0) + 22(100) - 900 = 1,300 (clearly less profit)

3) vertex (1400, 0)

P = 14x + 22y - 900 = 14(1400) + 22(0) - 900 = 18,700, which is the highest profit.

4 0
3 years ago
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