Answer:
<h2>
∠PQT = 72°</h2>
Step-by-step explanation:
According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.
Also from the diagram, ∠OQP + ∠PQT = ∠OQT;
∠PQT = ∠OQT - ∠OQP
Given ∠OQP = 18° and ∠OQT = 90°
∠PQT = 90°-18°
∠PQT = 72°
-6 - 3 = -9
12 - (-6) = 18
4 - 12 = -8
20 - 4 = 16
The first difference is -9. The third difference is -8.
Maybe the fifth difference is -7.
That makes the next term 13.
<span>3, -6, 12, 4, 20, 13</span>
Hello from MrBillDoesMath!
Answer:
See below
Discussion:
Triangles BAD and BCD are congruent by the SAS postulate.
* Side AD = DC because BD is the perpendicular bisector of AC.
* Angle ADB and CDB are both right angles, and hence equal, because
BD is the perpendicular bisector of AC)
Corresponding parts of congruent triangles are equal so angle BAD = angle BCD, which was to be proven.
Regards,
MrB
Equilateral: all sides are the same length
isosceles: two sides are the same length
obtuse: there is 1 obtuse angle
343 is the answer because 14 tens is 1 hundred and 4 tens