Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier.
canadian way
Find gcf: None
complet trinomial: 18n^2+57-10
find the product=10(18)
=-180
find the sum =57
-3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.
so (n-3)(n+60)
divide by a in this case it 18
so (n<u>-3</u>)(n+<u>60</u>)
18 18
do not divide. treat it like a fraction so you reduce it to lowest terms
(n<u>-3</u>)(n<u>-3)
</u> 18 10
<u /> at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"
=(18n-3)(10n-3)
therefore your answer is (18n-3)(10n-3)
I hoped this helped :)
Answer:
$43.20
Step-by-step explanation:
If each family member buys one ticket and one lunch, then for ticket price t we have the total expenditure as ...
5(t +6.50) = 248.50
t +6.50 = 49.70 . . . . . divide by 5
t = 43.20 . . . . . . . . . . subtract 6.50
The price of each train ticket is $43.20.
Answer:
60
Step-by-step explanation:
16/20 times 75
keeping in mind that a year has 12 months, thus 6 months is really 6/12 of a year.
