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aliya0001 [1]
3 years ago
15

Harper's house is 30 feet wide and 45 feet long. On a scale drawing, the house is 4 inches wide and 6 inches long, and Harper's

bedroom is 1.2 inches wide and 1.6 inches long.
What are the actual measurements of Harper's bedroom?

Enter your answers in the boxes.






Harper's bedroom is c feet wide and c feet long.
Mathematics
1 answer:
hammer [34]3 years ago
8 0
This is problem of ratio and proportion. to solve this, fisrt is calculate the convertion factor.
so the house is 30 feet in actual and 4 in wide on drawing
30 feet / 4 in = 7.5 feet / inso in every inch in the drawing is equivalent to 7.5 feet on actual.
1.2 in ( 7.5 ft/ in) = 9 ft
1.6 in ( 7.5 ft/ in) = 12 ft
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Janna jumped 156in in the long jump competition at the high school track meet . How many feet did Janna jump
Triss [41]
To find the number of feet she jumped you have to divide 156 by 12 because there are 12 inches in a foot

So 156/12 =13
So she jumped 13 feet
5 0
4 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
Which of the following equations has no solution?
daser333 [38]

Answer:

B. 3x+5−4x=−(x+8)

Explanation:

3x+5−4x=−(x+8)

Step 1: Simplify both sides of the equation.

3x+5−4x=−(x+8)

3x+5+−4x=−x+−8

(3x+−4x)+(5)=−x−8

−x+5=−x−8

−x+5=−x−8

Step 2: Add x to both sides.

−x+5+x=−x−8+x

5=−8

Step 3: Subtract 5 from both sides.

5−5=−8−5

0=−13

So, there is no solution

Hope this Helps!

8 0
3 years ago
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Answer:

540 degrees

Step-by-step explanation:

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There are 44 pens in all
5 0
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