let x be the first integer
x+ 2 the second integer ( two consecutive even )
smaller integer added to three times the larger <span>x + 3 ( x+2)
</span>two less than five times the smaller <span>5x - 2</span>
x + 3 ( x+2) = 5x - 2
x+3x +6 = 5x -2
x=8
the first integer = 8
the second is x+2 =10
D because (x-5)*x^2
I really hope this helps
Answer:
equation 1 has no solution
Step-by-step explanation:
when you compare each of the equations, all the equations gives a correct answer with the exception of equation 1
Answer:
A and E
Step-by-step explanation:
substitute and odd number into every equation :)
Answer:
10
Step-by-step explanation:
14+10=24-14=10
