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Alexxandr [17]
3 years ago
8

This is also seventh grade math and I need the value of X again please... 12(x+10)=24?

Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer: x = -8

Step-by-step explanation: To solve for <em>x</em> in this equation, our first task is to simplify the left side by distributing the 12 through both terms inside the parentheses.

When we do that, we get 12 times x which is

12x and 12 times 10 which is 120.

So we have 12x + 120 = 24.

Our next task is to isolate the x term by subtracting 120 from both sides of the equation. On the left, 120 - 120 cancels and we're left with 12x. On the right, 24 - 120 simplifies to -96 so we have 12x = -96.

To get <em>x</em> by itself, we divide both sides by 12 and <em>x = -8</em>.

Work is also attached in the image provided.

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The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
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The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.

That is,

Consider X be the length of the pregnancy

Mean and standard deviation of the length of the pregnancy.

Mean \mu =266\\

Standard deviation \sigma =15

For part (a) , to find the probability of a pregnancy lasting 308 days or longer:

That is, to find P(X\geq 308)

Using normal distribution,

z=\frac{X-\mu}{\sigma}

z=\frac{308-266}{15}

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Thus z=2.8

So P\left (X\geq 308  \right )=1-P(X

=1-P(z

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Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.

This the answer for part(a): 0.00256

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Given that the length of pregnancy is in the lowest 3​%.

The z-value for the lowest of 3% is -1.8808

Then X=\frac{X-\mu}{\sigma}\Rightarrow X=z*\sigma+\mu

This implies X=-1.8808*15+266=237.788

Thus the babies who are born on or before 238 days are considered to be premature.

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Step-by-step explanation:

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