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chubhunter [2.5K]
3 years ago
15

How can you use a number line to model and compare positive and negative rational numbers

Mathematics
1 answer:
elena-s [515]3 years ago
8 0
You can use a number line to compare negative and positive numbers because the negative numbers will be located after the 0 while the positive numbers will be located before the 0.
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Bob and Mark talk about their families. Bob says he has 3 kids, the product of their ages is 72. He gives another clue: the sum
Damm [24]
Not this riddle again


3 kids
what you are supposed to do is factor 72 and see their sums
1+1+72=74
1+2+36=39
1+3+24=28
1+4+18=23
2+2+18=22
1+6+12=19
2+3+12=17
1+8+9=18
2+4+9=15
2+6+6=14
3+3+8=14
3+4+6=13


notice that all the sums are different except for the 2 that add to 14
since there is not enough info, we can conclude that the sum was 14 and that the ages is either 2,6,6 or 3,3,8
after he says, "the youngest is called justice"
now we know there is a youngest
it cannot be 3,3,8 because 3 and 3 are both youngest
therefor the ages are
2,6 and 6 years old
7 0
3 years ago
Solve this equation<br> бу – 14 = 22<br> y =
zlopas [31]
6y -14 = 22
22+14=36
36/6= 6

Y=6
Hope this helps!
5 0
3 years ago
Read 2 more answers
The width of a rectangle is shown below: A coordinate plane with a point A at negative 3, 3 and C at negative 3, negative 2. If
noname [10]
The correct answer should be A, at positive 3 , and D , at positive 3
5 0
3 years ago
Read 2 more answers
I don’t know the answer or how to do this, help!
makvit [3.9K]

Answer:

B.

Step-by-step explanation:

y = x^2 - x - 12

y = (x-4)×(x+3) that means x it either 4 or -3

y = x + 3

for x = 4 ➡ y = 3+4 ➡7

for x = -3 ➡ y = -3 + 3➡0

(the answer key is most probably faulty there's no way for y to be 0 in both scenarios)

6 0
3 years ago
The wind power of a given wind turbine, P(v), depending on the wind speed in meters per second, v, can be found using the functi
PIT_PIT [208]

Answer:

18 m/s

Step-by-step explanation:

We used the given expression for the wind power: P(v)=0.002713v^3 replacing the power (on the left hand side of the equal sign) by 15.83 MegaWatts, and then solve for v which is raised to the power 3:

P(v)=0.002713v^3\\15.83=0.002713v^3\\\frac{15.83}{0.002713} =v^3\\v^3=5834.87\\v=\sqrt[3]{5834.87} =18.003\frac{m}{s}

5 0
3 years ago
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