Answer:
128
Step-by-step explanation:
32 x 4 = 128
o
32 + 32 + 32 + 32 = 128
Answer:
u = v2−2Egm−−−−−−−√
Step-by-step explanation:
2Eg = 2g (M2g(V2−U2)
2Eg = m(V2 - U2)
2Eg - mV2 - mU2
mU2 = mV2 - 2Eg
mU2m=mV2−2Egm
U2 = mV2−2Egm
= mV2m−2Egm
U2 = V2 - 2Egm
U = V2−2Egm−−−−−−−−√
Answer:
35000 - 2500m
Step-by-step explanation:
Height of the airplane before it starts descending = 35,000 feet
Rate of descend = 2500 feet per minute
This means for every 1 minute the height of airplane is decreasing by 2500 feet. So, for every "m" minutes the height of airplane will decrease by 2500m feet.
Let h(m) denotes the height of the airplane after m minutes. The equation for h(m) can be set up as:
Height of airplane at m'th minute = Original Height - Distance descended in m minutes
So,
h(m) = 35000 - 2500m
This expression describes the height of airplane after any number of minutes(m).
Answer:
Step-by-step explanation:
y = a * x(x - 3)(x + 1)^2
2,12 is used to find the value of a
y = a (2)(2 - 3)(2 + 1)^2
12 = a (2)(-1)(3)^2
12 = a (2) (-1) (9)
12 = - 18*a
12/-18 = a
a = - 2/3
y = (-2/3)*x*(x - 3)(x + 1)^2
None, he doesn't have any friends.
