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2 years ago

When is the estimation of products a useful tool?

1 answer:

3 0

The estimation of products are usefull so with you real answer, you can check back and fourth if you answer is reasonable

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!!!!!!!!!!!!!!!!!!!!

Andru [333]

Answer:

$f^{-1}(x)=4x+20$

Step-by-step explanation:

Given

$f(x)=\frac{x}{4}-5\\ \\y=\frac{x}{4}-5$

Swap x and y and solve for y

$y=\frac{x}{4}-5\\ \\x=\frac{y}{4}-5\\ \\x+5=\frac{y}{4}\\ \\4(x+5)=y\\\\y=4x+20$

Final answer

$f^{-1}(x)=4x+20$

Keep in mind that we need to swap the variables because a function and its inverse are symmetrical about the line y=x. See the graph below.

3 0

2 years ago

(09.02 HC)

Vesna [10]

We factor the equation to get:

-(x-25)^2+361

In the form a(x-h)^2+k, the vertex is (h, k), so the vertex is (25, 361). This means that the studio makes the most profit from selling 25 memberships, and thus makes 361 dollars.

B. The x-intercepts are the values of x for which f(x) is 0. This equation can be factored as (-a+6)(a-44)=0, with solutions 6 and 44. Therefore, by selling either 6 memberships or 44 memberships, the studio breaks even, neither making nor losing money.

4 0

2 years ago

What proportion of students are willing to report cheating by other students? A project put this question to an SRS of 180 under

krok68 [10]

Answer:

13.89% of students are willing to report cheating by other students.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 180

Number of students who reported cheating, x = 25

We have to find the proportion of the students are willing to report cheating by other students.

Proportion of students can be calculate as

$p = \dfrac{x}{n} = \dfrac{25}{180} = 0.1389\\\\\p = 0.1389\times 100\5\\p = 13.89\%$

Thus, 13.89% of students are willing to report cheating by other students.

8 0

2 years ago

WHICH SERIES OF TRANSFORMATIONS CAN BE USED TO SHOW THAT ABC~DEF?

elena-14-01-66 [18.8K]

Answer:

A) is correct

Step-by-step explanation:

7 0

1 year ago

What is twenty percent of two hundred and ten

marishachu [46]

The correct answer is 42

4 0

2 years ago

Read 2 more answers