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3 years ago

What is the value of x in the equation

Mathematics

1 answer:

MrRissso [65]3 years ago

8 0

Answer:

x = -3

Step-by-step explanation:

In an equation our aim is to find the value of what we are looking for as well as keeping the equation balanced. For example if we took away 1.4 only from one side then the equation would change so it's an important rule to keep in mind when solving equations, that you need to keep both sides of the equation the same.

0.7x - 1.4 = -3.5

→ First multiply everything by 10 to make everything into a whole number

7x - 14 = -35

→ Plus 14 to both sides to isolate 7x

7x = -21

→ Divide both sides by 7 to isolate 7

x = -3

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PLEASE HELP 50 COINS!!!!

tankabanditka [31]

Answer:

Therefore,

$AB=16.25\ units$

The Measurement of AB is 16.25 units.

Step-by-step explanation:

In Right Angle Triangle ABC

m∠C=90°

AC = 10.01 .....(Adjacent Side to angle A)

m∠A=52°

cos 52 ≈ 0.616

To Find:

AB = ? (Hypotenuse)

Solution:

In Right Angle Triangle ABC, Cosine Identity,

$\cos A= \dfrac{\textrm{side adjacent to angle A}}{Hypotenuse}\\$

Substituting the values we get

$\cos 52= \dfrac{AC}{AB}=\dfrac{10.01}{AB}$

But cos 52 ≈ 0.616 ....Given

$AB=\dfrac{10.01}{0.616}=16.25\ units$

Therefore,

$AB=16.25\ units$

The Measurement of AB is 16.25 units.

5 0

3 years ago

Solve the following differential equation: y" + y' = 8x^2

PtichkaEL [24]

Answer:

$y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$

Step-by-step explanation:

Let's find a particular solution. We need a function of the form $y= ax^3+bx^2+cx+d$ such that

$y'= 3ax^2+2bx+c$ and

$y''= 6ax+2b$

$y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2$

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a = 8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is $y_p= \frac{8}{3}x^3-8x^2+16x$ .

Now, let's find the solution $y_p$ of the homogeneus equation $y''+y'=0$ with the method of constants coefficients. Let $y=e^{\lambda x}$

$y'=\lambda e^{\lambda x}$

$y''=\lambda^2e^{\lambda x}$

then $\lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0$

$e^{\lambda x}(\lambda +\lambda^2)= 0$

$(\lambda +\lambda^2)= 0$

$\lambda (1+\lambda)= 0$

$\lambda =0$ and $\lambda)= -1$ .

So, $y_h = C_1 + C_2e^{-x}$ and the solution is

$y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$ .

5 0

2 years ago

What times what equals -7

Firlakuza [10]

Answer:

-7 x 1

hope that helped <3

8 0

2 years ago

A rectangle has an area 18sq cm.id its length and width are wjole numbera.what is its greatest possible perimeter

makkiz [27]

Answer:

38cm

Step-by-step explanation:

1. The perimeter of a square can be found with the formula $2 \times (width + length)$

2. Since its length and width are whole numbers, it must be either

1 x 18,

2 x 9 or

3 x 6

3. Using the formula in step 1, we can found that the perimeter in these cases are

respectively

4. Compare those perimeter we found in previous step, it's obvious that the greatest is 38. Solved.

3 0

3 years ago

Simplify: 6y + 5z + 8y – 3z

mezya [45]

Combine like terms. 6y + 8y is 14y. 5z - 3z is 2z. so the answer is 14y + 2z.

4 0

3 years ago

Read 2 more answers