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3 years ago

What is the value of x in the equation

Mathematics

1 answer:

MrRissso [65]3 years ago

8 0

Answer:

x = -3

Step-by-step explanation:

In an equation our aim is to find the value of what we are looking for as well as keeping the equation balanced. For example if we took away 1.4 only from one side then the equation would change so it's an important rule to keep in mind when solving equations, that you need to keep both sides of the equation the same.

0.7x - 1.4 = -3.5

→ First multiply everything by 10 to make everything into a whole number

7x - 14 = -35

→ Plus 14 to both sides to isolate 7x

7x = -21

→ Divide both sides by 7 to isolate 7

x = -3

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3 years ago

Read 2 more answers

Answer the following questions:

timama [110]

Answer:

Question 1: 76 dollars. ($76)

2. 1/5

3. 1/19

4. 1/5

Step-by-step explanation:

QUESTION 1:

228 (the amount Mrs. Nicci had) divided by 3 (children) is equal to 76

228/3 = 76

QUESTIONS 2, 3, AND 4.

2. Find the greatest common divisor (GCD). the GCD of 14 and 70 is 14. Then, divide the numerator and denominator by 14.

14/14 = 1

70/14 = 5

WHICH EQUALS 1/5!!

3. Find the greatest common divisor (GCD). the GCD of 5 and 95 is 5. Divide both the numerator and denominator by 5.

5/5= 1

95/5= 19

WHICH EQUALS 1/19!!

4. Find the greatest common divisor (GCD). the GCD of 12 and 60 is 12. So (like we have been doing for the whole part of this question), divide both the numerator and denominator by 12, which is the GCD.

12/12 = 1

60/12 = 5

WHICH EQUALS 1/5!!

Hope this helped.. I think this is like one of the longest Brainly answers I've recently had to type lol

4 0

2 years ago

In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o

melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

C. $z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D. $z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

$\hat p=\frac{33}{363}=0.0912$ estimated proportion of orders not accurate

$p_o=0.10$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558$

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

$z_{\alpha/2}=-1.96$ $z_{1-\alpha/2}=1.96$

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.

6 0

3 years ago