Answer: -1 < x < 8
x = 3
x ≠ 2
<u>Step-by-step explanation:</u>
Isolate x in the middle. Perform operations to all 3 sides.
-6 < 2x - 4 < 12
<u>+4 </u> <u> +4</u> <u>+4 </u>
-2 < 2x < 16
<u>÷2 </u> <u>÷2 </u> <u> ÷2 </u>
-1 < x < 8
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Isolate x. Solve each inequality separately. Remember to flip the sign when dividing by a negative.
4x ≤ 12 and -7x ≤ 21
<u>÷4 </u> <u>÷4 </u> <u> ÷-7 </u> <u>÷-7 </u>
x ≤ 3 and x ≥ 3
Since it is an "and" statement, x is the intersection of both inequalities.
When is x ≤ 3 and ≥ 3? <em>when x = 3</em>
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Isolate x. Solve each inequality separately.
15x > 30 or 18x < -36
<u>÷15 </u> <u> ÷15 </u> <u> ÷18 </u> <u>÷18 </u>
x > 2 or x < 2
Since it is an "or" statement, x is the union of both inequalities.
When we combine the inequalities, x is every value except 2.
x ≠ 2
Answer:
The total cost would be $90.61.
Step-by-step explanation:
10% of $82.37 is $8.237 and $82.37 + $8.237 rounds up to $90.61
The answer is -32. (2x-2x-2x-2)
The correct statements are Neither was correct and Joe used the height and radius to calculate the slant height.
<h3>How to find the square inches of paper needed.</h3>
The square inches of paper needed A = surface area of cone + area of overlap
<h3>Surface area of cone</h3>
The surface area of the cone is given by A = πr[r + √(h² + r²)] where
- r = radius of cone = 2 in and
- h = height of cone = 6 in.
So, A = πr[r + √(h² + r²)]
A = π × 2 × [2 + √(6² + 2²)]
A = π × 2 × [2 + √(36 + 4)]
A = π × 2 × [2 + √40]
A = π × 2 × [2 + 2√10]
A = 2π[2 + 2√10]
A = 4π + 4π√10
<h3>The area of overlap</h3>
The area of overlap A' = wL where
- w = width of overlap = 1/2 in and
- L = slant height of cone = √(h² + r²)
So, A' = wL
A' = w[√(h² + r²)]
A' = 1/2[√(6² + 2²)]
A' = 1/2[√(36 + 4)]
A' = 1/2[√40]
A' = 1/2 × 2√10
A' = √10
So, the number of square inches of paper needed is A" = A + A'
= 4π + 8π√10 + √10
Since the number of square inches of paper needed is 4π + 4π√10 + √10
So, the correct statements are Neither was correct and Joe used the height and radius to calculate the slant height.
Learn more about surface area of cone here:
brainly.com/question/24979679
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