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3 years ago

2x + 3y = 5x - y complete the missing value in the solution to the equation

Mathematics

2 answers:

salantis [7]3 years ago

6 0

Answer:

The missing value is 0.

Step-by-step explanation:

Given : Expression $2x + 3y = 5x - y$

To find : Complete the missing value in the solution to the equation (_,0) ?

Solution :

Write the expression,

$2x + 3y = 5x - y$

Take like terms together,

$3y+y = 5x-2x$

$4y=3x$

Now substitute y=0,

$4(0)=3x$

$3x=0$

$x=0$

So, The required point is (0,0).

Therefore, the missing value is 0.

Leto [7]3 years ago

4 0

Answer:

The missing value is(0,0)

Step-by-step explanation:

The complete question is:

2x+3y=5x-y

Complete the missing value in the solution to the equation.

( ,0)

Solution:

We have given:

2x + 3y = 5x - y

Combine the like terms:

2x-5x= -y-3y

-3x = -4y

Both negative signs will be cancelled out by each other.

So we have,

3x = 4y

We have given y = 0

Then

3x = 4*0

3x= 0

Divide both sides by 3

3x/3 = 0/3

x = 0

y=0

Therefore missing value is(0,0)

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Step-by-step explanation:

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3 years ago

The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz

marishachu [46]

The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$ , then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$ .

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$ .

Answer: the second polynomial is $3yz^2-3z^2-5y+7$ .

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3 years ago

Read 2 more answers

Consider the function g(x) = 10/x

ss7ja [257]

The correct answers are:
(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

Explanation:
(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = $\frac{10}{x}$ 

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = $\frac{10}{x}$ 

We can write it as:

g(x) = $\frac{10 * x^0}{x^1}$ 

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0

5 0

3 years ago

Read 2 more answers

A hiker starting at point P on a straight road wants to reach a forest cabin that is 2 km from a point Q, 3 km down the road fro

pantera1 [17]

Answer:

2.19 km

Step-by-step explanation:

If x is the distance she walks down the road before turning, then the total time is:

t = x/8 + √((3 − x)² + 2²) / 3

t = x/8 + √(9 − 6x + x² + 4) / 3

24t = 3x + 8√(13 − 6x + x²)

24t = 3x + 8(13 − 6x + x²)^½

Take derivative of both sides with respect to x.

24 dt/dx = 3 + 4(13 − 6x + x²)^-½ (-6 + 2x)

When t is a minimum, dt/dx = 0.

0 = 3 + 4(13 − 6x + x²)^-½ (-6 + 2x)

-3 = 4(13 − 6x + x²)^-½ (-6 + 2x)

3 / (6 − 2x) = 4(13 − 6x + x²)^-½

3 / (24 − 8x) = (13 − 6x + x²)^-½

(24 − 8x) / 3 = (13 − 6x + x²)^½

(24 − 8x)² / 9 = 13 − 6x + x²

576 − 384x + 64x² = 117 − 54x + 9x²

459 − 330x + 55x² = 0

Solve with quadratic formula.

x = [ 330 ± √((-330)² − 4(55)(459)) ] / 2(55)

x = (330 ± √7920) / 110

x = 2.19 or 3.81

Since 0 < x < 3, x = 2.19.

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3 years ago