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scZoUnD [109]
3 years ago
11

2x + 3y = 5x - y complete the missing value in the solution to the equation

Mathematics
2 answers:
salantis [7]3 years ago
6 0

Answer:

The missing value is 0.    

Step-by-step explanation:

Given : Expression 2x + 3y = 5x - y

To find : Complete the missing value in the solution to the equation (_,0) ?

Solution :

Write the expression,

2x + 3y = 5x - y

Take like terms together,

3y+y = 5x-2x

4y=3x

Now substitute y=0,

4(0)=3x

3x=0

x=0

So, The required point is (0,0).

Therefore, the missing value is 0.

Leto [7]3 years ago
4 0

Answer:

The missing value is(0,0)

Step-by-step explanation:

The complete question is:

2x+3y=5x-y

Complete the missing value in the solution to the equation.

( ,0)

<u>Solution:</u>

We have given:

2x + 3y = 5x - y

Combine the like terms:

2x-5x= -y-3y

-3x = -4y

Both negative signs will be cancelled out by each other.

So we have,

3x = 4y

We have given y = 0

Then

3x = 4*0

3x= 0

Divide both sides by 3

3x/3 = 0/3

x = 0

y=0

Therefore missing value is(0,0)

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3 years ago
The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz
marishachu [46]

The first polynomial is y -4yz^2-3 and let the second polynomial be P(y,z).

If the sum of two polynomials is -yz^2-3z^2-4y+4, then y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4.

Take the first polynomial from the left side to the right side:

P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7.

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3 0
3 years ago
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Consider the function g(x) = 10/x
ss7ja [257]
<span><span>The correct answers are:
</span><span>(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

</span><span>Explanation:
</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

g(x) = </span>\frac{10 * x^0}{x^1}<span>

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
</span>
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pantera1 [17]

Answer:

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Step-by-step explanation:

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