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Citrus2011 [14]
3 years ago
15

What is the slope of the line which passes through (1, 4) and (0, 1)?

Mathematics
1 answer:
madam [21]3 years ago
7 0
3/1 is the slope............,
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Leni [432]

\frac{36}{6} =\frac{6}{1}

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Consider the function f(x)= 1-|x-1|+|x+1| for -3<x<3. Recall that the absolute function can be represented as a piece wise
Kruka [31]
By the definition for the absolute value,

|x-1|=\begin{cases}x-1&\text{for }x\ge1\\-(x-1)&\text{for }x
|x+1|=\begin{cases}x+1&\text{for }x\ge-1\\-(x+1)&\text{for }x

So for the compound function f(x)=1-|x-1|+|x+1|, there are three intervals to consider. What happens when x? when -1\le x? when x\ge1?

You have

f(x)=\begin{cases}1-(-(x-1))+(-(x+1))=-1&\text{for }x
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3 years ago
What is the horizontal asymptote of the rational function f(x) = 3x / (2x - 1)?
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Answer:

Step-by-step explain

Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :

A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)

If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.

For the given function, there is no horizontal asymptote.

We can find the slant asymptote by using long division:

(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))

The slant asymptote is y=3/2x+3/4

6 0
3 years ago
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Step-by-step explanation:

sorry I would help is I neew

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32. Which of the following is horizontal ellipse
maria [59]

Answer:

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Step-by-step explanation:

Only one of them has a < b in ax² + by² = c formula, making its graph horizontal

All the rest are vertical, see attached

6 0
3 years ago
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