The temperature was -14°F at 8 a.m.
At noon is was 10 degrees warmer - the temperature increase was 10°F
-14°F + 10°F = -4°F
The tempertaure increase between noon and 4 p.m. was twice the previous increase in temperature, which was 10°F.
10°F x 2 = 20°F
We want to know the temperature at 4 p.m. so we just add it up to the previous result.
-4°F + 20°F = 16°F
16°F is the correct answer
C-d=b add to both sides d and will get
c-d+d=b+d
c=b+d
hope helped
Answer:
Step-by-step explanation:
Given the regression equation :
y=2+3x
Mean of y values ; y = 5.0
Where y is the predicted variable ; x = predictor variable
The predicted value of y for X = 2
Null: H0 = 5
Alternative H1 : ≠ 5
Sample size (n) = 10 pairs
Degree of freedom = n - 2 = 10 - 2 = 8
Answer:
C
Step-by-step explanation:
Answer:
Answer choice D, Infinitely many solutions.
Step-by-step explanation:
6x-24=6x-24
