I cant help i just needa answer something before i cant ask anything else
Answer:
8.898% will remain after 20000 years.
Step-by-step explanation:
First week need to know the half-life of carbon-14.
In this case it's 5,730 years.
There are calculators available online. (I'm too lazy to run through the equation.) 8.898% will remain after 20000 years.
I=√-1 and all the steps are there
We could use the Pythagorean theorem for this kind of problem I think:
A^2 + B^2 = C^2
6^2 + 16^2 = C^2
36 + 256 = C^2
292 = C^2
17.08 = C
C = 17.1 to the nearest tenth
Sorry if it’s wrong and glad I could help if it’s right ❤️❤️ Take care!
The cost of each stone sphere is $ 36.81
<em><u>Solution:</u></em>
Given that,
An architect plans to buy 5 stone spheres and 3 stone cylinders
For the same amount, she can buy 2 stone spheres and 6 stone cylinders
Let "x" be that same amount
Let "a" be the cost of each stone sphere
Cost of each stone cylinder = $ 36.81
Therefore,
x = 5 stone spheres and 3 stone cylinders
x = 5a + 3(36.81)
Similarly,
x = 2 stone spheres and 6 stone cylinders
x = 2a + 6(36.81)
Equate both,

Thus cost of each stone sphere is $ 36.81