56 = 2 x 2 x 2 x 732 = 2 x 2 x 2 x 2 x 2
GCF = 2 x 2 x 2 =8
Rewrite 56+32 as the product of the GCF and a sum:
56 + 32 = 8 (7+4)
Total height of lumber, H = 10 1/2 feet = 21/2 feet .
Height of side panel, h = 5 2/3 feet = 17/3 feet .
Now,
Extra lumber required, L = 2 × Height of side panel - Total height of lumber
![L=[2\times (\dfrac{17}{3})]-\dfrac{21}{2}\\\\L = \dfrac{5}{6}\ feet](https://tex.z-dn.net/?f=L%3D%5B2%5Ctimes%20%28%5Cdfrac%7B17%7D%7B3%7D%29%5D-%5Cdfrac%7B21%7D%7B2%7D%5C%5C%5C%5CL%20%3D%20%5Cdfrac%7B5%7D%7B6%7D%5C%20feet)
Therefore, extra lumber required is 
feet.
Hence, this is the required solution.
Answer:
multiple by -3
and that will be the answer
<h3>
Answer: 8/25</h3>
=======================================================
Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
Looking at the units, 756 meters divided by 6 m/s will give you the seconds that you need.
So for A) 756/6 = 126
For B, you take the answer from A, and subtract 18 seconds, which would make it 108. Then you take the distance, 756 and divide by 108, that will be the speed.
