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3 years ago

Factor the expression using the GCF 18p + 26

Mathematics

2 answers:

romanna [79]3 years ago

5 0

2(9p + 13)

Hope this helps!!!!

Klio2033 [76]3 years ago

4 0

2(9p+13) I hope it helpssss

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Help me please asap

Sav [38]

Answer:1/13

Step-by-step explanation:

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3 years ago

How many times does the digit 6 appear in the list of all integers from 1 to 100?

amm1812

20 times I think.
6,16,26,36,46,56,60,61,62,63,64,65,66,67,68,69,76,86, and 96

5 0

4 years ago

Read 2 more answers

A regular tank is being designed with an internal catwalk around the inside as shown. For functional reasons, the walk way canno

Andru [333]

Answer is in the file below

tinyurl.com/wtjfavyw

3 0

3 years ago

A cylinder has a base radius of 4m and a height of 6m. What is its volume in cubic m, to the nearest tenths place?

Ronch [10]

<h3>Answer:</h3>

301.6 cubic meters

<h3>Step-by-step explanation:</h3>

A cylinder is a shape with straight sides with circular or oval cross-sections. We know that the cylinder in the question must be a circular cylinder due to its radius description.

Volume Formula

A circular cylinder has a volume of $V=\pi r^2h$ . In this equation, V is the volume, r is the radius, and h is the height. The question tells us that r=4m and h=6m. So, we can plug these values into the formula.

Solving for Volume

To solve plug the values into the formula and rewrite the equation.

$V=\pi *4^2*6$

Next, apply the exponents.

$V=\pi *16*6$

Then, multiply the constants.

$V=\pi *96$

Finally, multiply the remaining terms. Remember to use the pi button on the calculator and not an estimation to get a more exact value.

$V=301.6$

Make sure your answer is rounded to the correct digit. This means that the volume must be 301.6 cubic meters.

6 0

2 years ago

A sample of 173 students using Method 1 produces a testing average of 88. A sample of 127 students using Method 2 produces a tes

Lerok [7]

Answer:

43 < μ₁ - μ₂ < 49

Step-by-step explanation:

Sample 1:

Mean x₁ = 88

Sample size n₁ = 173

Sample standard deviation s₁ = 12,22

Sample 2:

Mean x₂ = 53,5

Sample size n₂ = 127

Sample standard deviation s₂ = 13,59

CI 95 % α = 5% α = 0,05 α/2 = 0,025

We need to find:

( x₁ - x₂ ) - tα/2,v *√ (s₁²/n₁ ) + (s₂²/n₂) < μ₁ - μ₂ < ( x₁ - x₂ ) + tα/2,v *√ (s₁²/n₁ ) + (s₂²/n₂)

v = degree of fredom

v = [ ( s₁²/n₁ + s₂²/n₂)² / (s₁²/n₁)² /n₁-1 + (s₂²/n₂)²/n₂-1

v = [ (0,86 + 1,45 ) / 0,0043 + 0,017

v = 2,31 / 0,0213

v = 108

Then t 0,025, 108 from t table is: We will take v = 100

t = 1,984

Now

√ (s₁²/n₁ ) + (s₂²/n₂) = √ 0,86 + 1,43

√ 2,3 = 1,51

Then: CI:

(173 - 127 ) - 1,984*1,51 < μ₁ - μ₂ < ( 173 - 127 ) + 1,984*1,51

46 - 3 < μ₁ - μ₂ < 46 + 3

43 < μ₁ - μ₂ < 49

8 0

3 years ago