The snowman is made of 3 spheres (balls) of snow. The diameters, from top to bottom, are 12, 16, 18 inches
Therefore, the radii of the 3 spheres are, respectively, 6, 8, and 9 inches.
The volume of a sphere of radius, r, is given by the formula: V = 4/3 π r3
So, the total volume of snow is the sum of the 3 volumes: V = 4/3 π (63 + 83 + 93)
= 4/3 π (1,457)
=6,099.97
Your answer would be D. 6,099.97
I hope this helps!
Answer: 490 grams of the first alloy should be used.
30 grams of the second alloy should be used.
Step-by-step explanation:
Let x represent the weight of the first alloy in grams that should be used.
Let y represent the weight of the second alloy in grams that should be used.
A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is
0.15x and 0.2x
The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is
0.3y and 0.5y
If the alloy to be made contains 82.5 g of gold, it means that
0.15x + 0.3y = 82.5 - - - - - - - - - - - -1
The second alloy would also contain 113 g of lead. This means that
0.2x + 0.5y = 113 - - - - - - - - - - - - -2
Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes
0.03x + 0.06y = 16.5
0.03x + 0.075y = 16.95
Subtracting, it becomes
- 0.015y = - 0.45
y = - 0.45/- 0.015
y = 30
Substituting y = 30 into equation 1, it becomes
0.15x + 0.3 × 30 = 82.5
0.15x + 9 = 82.5
0.15x = 82.5 - 9 = 73.5
x = 73.5/0.15
x = 490
Answer:
4
Step-by-step explanation:
Answer:
Maggie is incorrect.
Step-by-step explanation:
PEMDAS tells us the order of operations and the steps of solving a mathematical statement. It states that exponents must be performed before multiplication or division.
P - Parentheses
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction
Therefore, to solve 12÷3² correctly, 3² needs to be simplified to 9 <em>before</em> dividing.
I hope this helps!
1000= 10^3 -- ten to the third power
assuming you mean whole numbers,
graba calculator, figure out what
1^3, 2^3 3^3 ... 9^3 are
or
1x1x1
2x2x2
3x3x3
...
9x9x9
