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2 years ago

7 1

Mathematics

1 answer:

Tatiana [17]2 years ago

3 0

9514 1404 393

Answer:

-10 or (0, -10) as an ordered pair

Step-by-step explanation:

The y-intercept is the value of y when x=0. Using x=0 in the equation gives ...

y -2 = 3(0 -4)

y = -12 +2

y = -10 . . . . . the y-intercept

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As the number of pages in a photo book increases, the price of the book also increases. There is an additional shipping charge o

BartSMP [9]

Let the maximum number of pages Jennifer can have be = x

Amount Jennifer has (P) = $62.10

Given equation is :

P = $(20+0.5x)+0.15(20+0.5x)$

Price is given = 62.10 , so equation is :

$62.10=(20+0.5x)+0.15(20+0.5x)$

$62.10=20+0.5x+3+0.075x$

$62.10=23+0.575x$

$0.575x=39.10$

$x=68$

Hence, Jennifer can have a maximum of 68 pages in her book.

5 0

3 years ago

dee’s age is twice Max’s age plus two more.Write an expression to represent Dee’s age.Then evaluate the expression when Max is 7

Mandarinka [93]

D=2x+2

X=7

Plug in the value for Max's age.

D=2(7)+2

D=14+2

D=16

Max is 7

Dee is 16

5 0

2 years ago

Read 2 more answers

Find four consecutive even integers such that if the sum of the first and third is multiplied

Alenkasestr [34]

Answer:

Step-by-step explanation:

-8-10,-12-14

-8 plus -12 is -20

-20 times 5 is -100

-14 times 8 is -112

-100 is 12 more than -112

6 0

2 years ago

Convert 6.42 kilograms to grams. 0.00642 g 64.2 g 642 g 6,420 g

Katarina [22]

1 kilogram (kg) equals to 1000 grams (g). Since you have 6.42 kilograms, divide 6.42 kilograms to 1000 grams. Your final answer is 6420 grams in total.

4 0

2 years ago

Solve the equation using the quadratic formula. Enter each solution in simplest form.

sergeinik [125]

For this case we have the following quadratic equation:

$x ^ 2-4x + 23 = 0$

The solutions will be given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = -4\\c = 23$

Substituting the values we have:

$x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}$

We have two roots:

$x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}$

ANswer:

$x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}$

6 0

3 years ago