The answer is a) equilateral triangle. If you want to inscribe a hexagon inside a circle, the tools or constructions that should be used is 6 equilateral triangles. If you draw a hexagon inscribed in a circle and draw radii to the corners of the hexagon, you will create triangles, six of them.<span>
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Answer:
y=-5/3x+20
Step-by-step explanation:
Let the equation of the required line be represented as ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
This line is perpendicular to the line ![\[y=\frac{3}{5}x+10\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B3%7D%7B5%7Dx%2B10%5C%5D)
![\[=>m*\frac{3}{5}=-1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%2A%5Cfrac%7B3%7D%7B5%7D%3D-1%5C%5D)
![\[=>m=\frac{-5}{3}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%3D%5Cfrac%7B-5%7D%7B3%7D%5C%5D)
So the equation of the required line becomes ![\[y=\frac{-5}{3}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2Bc%5C%5D)
This line passes through the point (15.-5)
![\[-5=\frac{-5}{3}*15+c\]](https://tex.z-dn.net/?f=%5C%5B-5%3D%5Cfrac%7B-5%7D%7B3%7D%2A15%2Bc%5C%5D)
![\[=>c=20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ec%3D20%5C%5D)
So the equation of the required line is ![\[y=\frac{-5}{3}x+20\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2B20%5C%5D)
Among the given options, option 4 is the correct one.
Answer:
$1913.34
Step-by-step explanation:
$1784 (original amount) * 7.25% (sales tax) = $129.34 Tax paid
129.34 + 1784 = Price after tax
First write the equation 8 + 12 > x because according to the triangle property, the sum of any 2 sides have to be greater than the third side. This means that the difference of any two sides should be smaller than the third side.
So, the answer would be 4 < x < 20.
Answer:
option D: 27.5 square units
Step-by-step explanation:
Divide the polygon in 6 figures
see the attached figure
Area of figure 1 (right triangle)
A1=(1/2)(3)(3)=4.5 units²
Area of figure 2 (rectangle)
A2=(1)(3)=3 units²
Area of figure 3 (rectangle)
A3=(1)(3)=3 units²
Area of figure 4 (right triangle)
A4=(1/2)(3)(3)=4.5 units²
Area of figure 5 (right triangle)
A5=(1/2)(4)(5)=10 units²
Area of figure 6 (right triangle)
A6=(1/2)(1)(5)=2.5 units²
The total area is equal to
At=A1+A2+A3+A4+A5+A6
At=4.5+3+3+4.5+10+2.5=27.5 units²