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Varvara68 [4.7K]
3 years ago
7

I am a number between 60 and 100.My ones digital is less than my tens digit I am a prime number what number am i

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0
Dear Cody1111, 97 is a possible number 7 is less than 9 and 97 is a prime number.
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Determine whether the equation Y=x^2 +13 represents a linear or non linear function and explain
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Answer:

yés it is linear because

two variables that gives a straight line when plotted on a graph.

if it was correct tell me good or it was mistake tell me truth

Step-by-step explanation:

hope it was correct

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Which plane figure generates a cylinder when it rotates about the dashed line?
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I am not exactly sure, but I am almost positive it is a spere 
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Jeanette is starting a business selling handmade necklaces. She has decided to invest an initial amount of $400 for advertising,
lana66690 [7]

Answer:

25 necklaces

Step-by-step explanation:

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3 years ago
Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come f
AlladinOne [14]

Answer:

z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

Now we can calculate the p value with the following probability:

p_v =P(z>2.43)=0.0075 \approx 0.008  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

\hat p=0.64 estimated proportion of interest

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true proportion is higher than 0.5:  

Null hypothesis:p =0.5  

Alternative hypothesis:p > 0.5  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

Now we can calculate the p value with the following probability:

p_v =P(z>2.43)=0.0075 \approx 0.008  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

7 0
4 years ago
Consider this expression.
USPshnik [31]

Answer:

-16

Step-by-step explanation:

m^2 + n^2

-5^2 + 3^2 = -16

5 0
2 years ago
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