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Gelneren [198K]
3 years ago
11

Suppose DK is an angle bisector of △DEF. Given: EK=2, FK=5, DF=10. Find DE.

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0

Answer:

DE=4

Step-by-step explanation:

We have been provided a graph of a triangle and we are asked to find the length of segment DE.

Angle bisector theorem states that if a ray bisects an angle of a triangle, then it bisects the opposite side of triangle into segments that are proportional to other two sides.

By angle bisector theorem we can set proportions of the given sides as:

\frac{DE}{EK}=\frac{DF}{FK}

Upon substituting our given values in above proportion we will get,

\frac{DE}{2}=\frac{10}{5}

Upon multiplying both sides of our equation by 2 we will get,

\frac{DE}{2}\times 2=2\times \frac{10}{5}

DE=2\times 2

DE=4

Therefore, the length of segment DE is 4 units.

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100 square centimeters means the dimensions are 10x10
but the actual floor will be 1cm:2ft
so 10cm=20feet
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4 0
3 years ago
Which of the following expressions is equal to -3X2-27?
ale4655 [162]

Answer: B

Step-by-step explanation:

-3x^2-9xi+9ix-27

-3x^2-27

8 0
3 years ago
Wilmer went up a hill for x minutes at a speed of y kilometers per minutes. Then he went down the same path at a speed of z kilo
dedylja [7]

Answer:

xy=wz

Step-by-step explanation:

Given that:

Speed of Wilmer up the hill = y km/min

Time taken up the hill = x minutes

Speed of Wilmer down the hill = z  km/min

Time taken up the hill = w minutes

Distance can be calculated by multiplying the Speed with Time i.e.

The formula for distance is given as:

Distance = Speed \times Time

Distance up the hill = y\times x =xy\ kilometers

Distance down the hill = z\times w =wz\ kilometers

It is well known that, the distance up the hill and down the hill will be same.

Putting both the values equal, we get:

xy=wz

4 0
2 years ago
Mary throws her Grandma’s favorite crystal dish out the second floor window, which is 6 meters from the ground. She is really up
wlad13 [49]

we know that

acceleration due to gravity is 9.8m/s^2

so, we get

a(t)=9.8

and acceleration will always be constant

we know that

integral of acceleration is velocity

so, we can integrate both sides

\int \:a\left(t\right)dt=\int \:9.8dt

v(t)=9.8t+C

we are given

v(0)=35m/s

we can use it and find C

v(0)=9.8*0+C

35=9.8*0+C

C=35

now, we can plug it back

v(t)=9.8t+35

we know that

integral of velocity is height

we can integrate it again

\int \:v\left(t\right)dt=\int \:\left(9.8t+35\right)dt

s(t)=\int \:\left(9.8t+35\right)dt

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now, we have

s(0)=6

we can use it and find C

s(0)=4.9(0)^2+35(0)+C

6=4.9(0)^2+35(0)+C

now, we can plug back C

C=6

and we get

s(t)=4.9t^2+35t+6.............Answer

4 0
3 years ago
Read 2 more answers
A total of 484 tickets we’re sold for the school play. They Either adult or student tickets. There were 66 Fewer student tickets
choli [55]

Answer:

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Let x = the number of adult tickets sold

Let x + 61 = the number of student tickets sold

x + x + 61 = 761

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4 0
3 years ago
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