Which expression represents 12 times a number, n, minus 6?

In the game of SCRABBLE, you select letters from the group in the pot that are not already on the board or in your hand or someo

ra1l [238]

333333333.3333333462804098816544788183775829905887615527590500299873666178495950918764647003852

8 0

3 years ago

Given the points A(3, 1), B(6, y) and C(12, -2) find the value(s) of y if…

Musya8 [376]

Answer:

B. The lines AB and BC are perpendicular.

Step-by-step explanation:

If all the points are doubled on the x-axis, they are perpendicular.

hope this helps.

8 0

2 years ago

Read 2 more answers

Select the correct answer.

Anastaziya [24]

Answer:

yo

Step-by-step explanation:

8 0

3 years ago

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$