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Angelina_Jolie [31]
4 years ago
10

A firm has 25 senior and 26 junior partners. A committee of three partners is selected at random to represent the firm at a conf

erence. In how many ways can at least one of the junior partners be chosen to be on the committee?
Business
1 answer:
Sergio [31]4 years ago
6 0

Answer:

There are 18,525 ways to choose at least one of the junior partners to be on the committee.

Explanation:

If all partners can be chosen in any way the choices would be combinations of any 3 partners from all 51 partners. The number of ways to arrange it would be:

A = {51 \choose 3} = \frac{51!}{3!(51-3)!}  = 20,825

The opposite of choosing at least one junior partner is to choose no junior partner. Those choices would be combinations of any 3 partners from 25 senior partners. The number of ways to arrange it would be

B =  {25 \choose 3} = \frac{25!}{3!(25-3)!}  = 2,300

So the number of ways to choose at least one of the junior partners to be on the committee would be: A - B = 20,825 - 2,300 = 18,525

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Answer:

see below

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3 years ago
Read 2 more answers
The break-even point is the sales level at which a company_______________.a. incurs a loss. b. contribution margin equals fixed
Neporo4naja [7]

Answer:

b. contribution margin equals fixed costs

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The break even point is the point in which the firm has no profit and no loss situation. When it meets we called as break even point.

So, the break even point is the point at which the profit is zero plus the contribution margin equals to the fixed cost i.e means

Contribution margin = Fixed cost

Sales - variable cost = Fixed cost

If both are equal so it seems the profit is zero

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