Answer:
(k-x)(x+y)
Step-by-step explanation:
x×(k-x)+y×(k-x)
=(k-x)(x+y)
Answer:
4 + 12 + 36 + ...
Step-by-step explanation:
4, 12, 36, ... is a geometric sequence, it has a common ratio of ![r=\frac{36}{12}=\frac{12}{4}=3](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B36%7D%7B12%7D%3D%5Cfrac%7B12%7D%7B4%7D%3D3)
When we add the terms of a geometric sequence we get a geometric series.
4+12+36+ ... is a geometric series, it has a common ratio of ![r=\frac{36}{12}=\frac{12}{4}=3](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B36%7D%7B12%7D%3D%5Cfrac%7B12%7D%7B4%7D%3D3)
4 + 12 + 20 + ... is not a geometric series because it has no common ratio
![\frac{20}{12}\ne \frac{12}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B12%7D%5Cne%20%5Cfrac%7B12%7D%7B4%7D)
The second choice is correct
Answer:5x^4
Step-by-step explanation: Simplify the radical by breaking the radicand up into a product of known factors, assuming real numbers
3x -y ⩾ 6
3x - 6 ⩾ y
now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".
if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,
3(4) - 0 ⩾ 6
12 - 0 ⩾ 6
12 ⩾ 6
is 12 really greater or equals to 6? well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.
now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.
check the picture below.
That’s 29 I thinking I don’t know