Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
Hey there!
Find out how many men there are by subtracting the number of woman by the total number of students
32-9= 23
23 students are men
To find the percent just simply multiply. *cross multiply
23/32 *100= 71.87
100*23= 2300
2300/32= 17.875
17.875 rounds to 17.9
71.9% are men
Answer: 12.3
Step-by-step explanation: It's 12.3 because the other 3 is in the hundredths place and the rule says 5 or more round,4 or less stays the same
That easiliy false. You can prove this by observing that all integers are, in particular, rational numbers. So, for instance, you can think of 4 as 
, so 
And obviously, you have 
It is true that the square of every rational number between 0 and 1 is smaller than the number itself.
But since not all rational numbers are between 0 and 1, the general claim is false.
36/x=100/25
<span>(36/x)*x=(100/25)*x </span>
<span>36=4*x </span>
<span>36/4=x </span>
<span>9=x </span>
<span>x=9</span>
