Answer:
b = 159 m
a = 103 m
angle B is 57 degrees
Step-by-step explanation:
Let’s start with getting the measure of angle B
Mathematically, since we have a right triangle , we have to subtract the given angle from 90 to get the other acute angle
So we have the measure of B as;
90-33 = 57 degrees
To get the value of a, we use the appropriate trigonometric ratio
a faces the angle 33, that makes it an opposite to that angle
190 faces the right angle and that makes it the hypotenuse
Mathematically , the relationship between the two is that trigonometrically, they are related by the sine which is the ratio of the opposite to the hypotenuse
so, we have it that;
sine 33 = a/190
a = 190 * sine 33
a = 103 m
to get b, it is adjacent to the given angle
So with the hypotenuse, the ratio between it and the hypotenuse is the cosine
so;
cos 33 = b/190
b = 190 * cos 33
b = 159 m
X=12 because you would sub the 3 on both sides
Answer:
42.25
Step-by-step explanation:
65*35%=22.75
65-22.75=42.25
<u>To find the density:</u>
⇒ must find the relationship between the density, mass, and volume
⇒ 
<u>Let's examine the information given:</u>
- weight: 1890g
- dimensions: 8cm * 5cm* 5cm
<u>Let's first find the volume:</u>
⇒ the volume is the dimensions multiplied together

<u>LEt's calculate the density now:</u>

<u>Answer:</u> The density of the copper is <u>9.45g/cm^3</u> or <u>Choice (A)</u>
<u></u>
Hope that helps!
Answer: (x - 4) • (3x + 2)
Step-by-step explanation: