Answer:
The length of the diagonal HJ is 10.82 units
Step-by-step explanation:
* Lets revise the rule of the distance between two points
-
, where
and
are the two points
* Lets use this rule to find the length of the diagonal HJ
∵ The coordinates of point H are (-4 , 3)
∵ The coordinates of point J are (5 , -3)
∴
and 
∴
and 
- Lets find the length of the diagonal HJ by using the rule above
∴ HJ = 
∴ HJ = 
∴ HJ = 10.82
* The length of the diagonal HJ is 10.82 units
8 x .75 x 1.50 = 9 that is your answer
ANSWER
Quotient:

Remainder:

EXPLANATION
The given functions are

and

We want to find the remainder and quotient when f(x) is divided by g(x).
We perform the long division as shown in the attachment.
The quotient is

The remainder is
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