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EastWind [94]
3 years ago
8

You have $150 to spend at a store. If you shoes cost $30 and belts cost $25, write an equation that represents the different way

s that you could spend a total of $150
Mathematics
2 answers:
Yuliya22 [10]3 years ago
6 0

Answer:

you could buy a pair of shoes and a belt still have 95 dollars to spend

nikitadnepr [17]3 years ago
4 0
30+30+25+25=140 but no way to get 150
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Molodets [167]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Equation of line passing through given points :

Let's proceed with two point form ~

\qquad \sf  \dashrightarrow \: y - y1 =  \cfrac{y2 - y1}{x2 - x1} (x - x1)

Assume :

\qquad \sf  \dashrightarrow \: y - 3=  \cfrac{3 - 3}{ - 4 - 6} (x - 6)

\qquad \sf  \dashrightarrow \: y - 3=  \cfrac{0}{ - 10} (x - 6)

\qquad \sf  \dashrightarrow \: y - 3 = 0

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1 year ago
Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°
jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1,  ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3  and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

                 =540°=180°

                 =360°.

Hence, the sum of all the external angles of a triangle is 360°.

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