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olya-2409 [2.1K]
3 years ago
8

Noa hopes to pick the winning ticket during her math class’s raffle. the student who picks the ticket with a true statement will

win. which is the winning ticket?
4(x-5)=35 is equivalent to 4x=40
8(x-7)=35 is equivalent to 8x=28
2(x-6) = -35 is equivalent to 2x=-23
9(x-6)=-35 is equivalent to 9x=-29
Mathematics
2 answers:
sasho [114]3 years ago
8 0

Answer:

3rd option is the correct answer

Natali5045456 [20]3 years ago
4 0

Answer: The winning ticket is 2(x-6)=-35 is equivalent to 2x=-23.



Step-by-step explanation:

Let's check all the options

4(x-5)=35 is not equivalent to 4x=40

\text{since }4(x-5)=35\\\Rightarrow4x-20=35\\\Rightarrow4x=35+20\\\Rightarrow4x=55

8(x-7)=35 is not equivalent to 8x=28


\text{since }8(x-7)=35\\\Rightarrow8x-56=35\\\Rightarrow8x=35+56\\\Rightarrow8x=91

2(x-6)=-35 is equivalent to 2x=-23


\text{since }2(x-6)=-35\\\Rightarrow2x-12=-35\\\Rightarrow2x=-35+12\\\Rightarrow2x=-23

9(x-6)=-35 is not equivalent to 9x=-29

\text{since }9(x-5)=-35\\\Rightarrow9x--40=-35\\\Rightarrow9x=-35+40\\\Rightarrow9x=5

Thus, the winning ticket is 2(x-6)=-35 is equivalent to 2x=-23.

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Martin Luther King is a famous African American and he shouldn’t be too hard to write about.
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3 years ago
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Find the y and x and the given slope of the given line: Line E.​
azamat

Answer:

change in y: 0

change in x: 5

slope: 0

Step-by-step explanation:

Sub these two points from Line E into the gradient formula (you can search this up on the internet) and you would get 0/5

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6 0
3 years ago
If 12 cats can catch 6 rats in 2 hours, how many hours would it take 50 cats to catch 75 rats?
sleet_krkn [62]

Answer:

50 cats would take 6 hours to catch 75 rats.

Step-by-step explanation:

After reading the statement we noticed the existence of two relationships:

1) <em>The amount of cats is directly proportional to the quantity of caught rats.</em>

2) <em>The amount of cats is inversely proportional to time taken to catch rats. </em>

That is to say:

n \propto \frac{x}{y}

n = k\cdot \frac{x}{y} (Eq. 1)

Where:

n - Amount of cats, dimensionless.

x - Amount of caught rats, dimensionless.

y - Time, measured in hours.

k - Proportionality ratio, measured in hours.

Then, we obtain the following relationship by eliminating the proportionality ratio in (Eq. 1):

\frac{n_{1}\cdot y_{1}}{x_{1}} = \frac{n_{2}\cdot y_{2}}{x_{2}} (Eq. 2)

Where:

n_{1}, n_{2} - Initial and final amounts of cats, dimensionless.

x_{1}, x_{2} - Initial and final amounts of caught rats, dimensionless.

y_{1}, y_{2} - Initial and final times, measured in hours.

Now we clear final time in (Eq. 2):

y_{2} = y_{1}\cdot \left(\frac{n_{1}}{n_{2}} \right)\cdot \left(\frac{x_{2}}{x_{1}} \right)

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y_{2} = (2\,h)\cdot \left(\frac{12}{50} \right)\cdot \left(\frac{75}{6}\right)

y_{2} = 6\,h

50 cats would take 6 hours to catch 75 rats.

7 0
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42%
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