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3 years ago

70% of what number is 42?

Mathematics

2 answers:

Fed [463]3 years ago

8 0

The answer is 60 i think

Rudik [331]3 years ago

7 0

Your answer should be 60
HOPE THIS HELPS

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Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = t 25 − t2 , [−1, 5]

Zina [86]

Answer: Absolute minimum: f(-1) = -2 $\sqrt{6}$

Absolute maximum: f( $\sqrt{12.5}$ ) = 12.5

Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = $t\sqrt{25-t^{2}}$

f'(t) = $1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)$

f'(t) = $\sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }$

f'(t) = $\frac{25-2t^{2}}{\sqrt{25-t^{2}} }$ = 0

For this function to be zero, only denominator must be zero:

$25-2t^{2} = 0$

t = ± $\sqrt{2.5}$

$\sqrt{25-t^{2}}$ ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = $-\sqrt{2.5}$ and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = $t\sqrt{25-t^{2}}$

f(-1) = $-1\sqrt{25-(-1)^{2}}$

f(-1) = $-\sqrt{24}$

f(-1) = $-2\sqrt{6}$

f( $\sqrt{12.5}$ ) = $\sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}$

f( $\sqrt{12.5}$ ) = 12.5

f(5) = $5\sqrt{25-5^{2}}$

f(5) = 0

Therefore, absolute maximum is f( $\sqrt{12.5}$ ) = 12.5 and absolute minimum is

f(-1) = $-2\sqrt{6}$ .

8 0

3 years ago

What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)?

Monica [59]

Answer:

y = 4x + 16

Step-by-step explanation:

y - 1 = 4(x + 3)

Has a slope of 4

y = 4x + c

32 = 4(4) + c

32 - 16 = c

c = 16

y = 4x + 16

7 0

4 years ago

Read 2 more answers

What is the constant rate of change from the table?

Usimov [2.4K]

Answer:

whats the table?

Step-by-step explanation:

4 0

3 years ago

Find the sum and express it in simplest form (8a^2 + 6a + 5) + (-3a^2 - 2a)

PIT_PIT [208]

What we are going to do with this problem is combine all the like terms.
so to begin, we notice that there are two numbers with a^2 involved, and two numbers with an a.

thus:
8 $a^{2}$ +(-3 $a^{2}$ is going to equal 5 $a^{2}$ because adding a negative is just like subtracting.

then we move on to (6a)-(2a) giving us 4a
5 is the only term that stays the same because there are no other similar terms.
last but not least, put the equation together!

answer: 5 $a^{2}$ +4a+5