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Oksanka [162]
3 years ago
12

How do you solve the fraction 2 1/2 - 6

Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0
You could easily change the 2 1/2 to a 2.5 and do 2.5-6=-3.5
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A line with slope of -3 passes through the points ( x , -6 ) and ( -2 , 6 ). What is the missing x-coordinate?
valentina_108 [34]
We can use the formula y2-y1/x2-x1 to find the answer. Therefore, we would have: 6-(-6)/-2-x equalling -3. So, 12/-2-x = -3. We multiply both sides by -2-x and get 12 = -3(-2 - x), then 12 = 6+ 3x. We then get 6 = 3x, and by dividing both sides by 2 we get x = 2.
6 0
2 years ago
Tim is training for a marathon, He ran 24 miles in 5 days, if he ran the same distance each diay, how far did he run per day?
malfutka [58]

Answer:

I believe its 4.8, which is confusing seeing as its not an option.

Step-by-step explanation:

If he ran 24 miles in 5 days, divide 24 by 5 to get your answer.

7 0
3 years ago
What is the slope of a line that is parallel to y=3/4x+2
k0ka [10]
A line that is parallel to another has exactly the same slope as the other.

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4 0
3 years ago
POSSIBLE POINTS: 5.88
Bess [88]

The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)

<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>

The given parameters are:

Perimeter = 210 meters

Let the length parallel to the wall be represented as z and the width be x

So, the perimeter of the fence is

P = 2x + z

This gives

210 = 2x + z

Make x the subject

x = 1/2(210 - z)

The area of the wall is calculated as

A = xz

So, we have

A = 1/2(210 - z) * z

This gives

A = z/2(210 - z)

Rewrite as

A(z) = z/2(210 - z)

Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)

Read more about functions at

brainly.com/question/1415456

#SPJ1

5 0
1 year ago
Which value of k makes the inequality 11+2k&gt;19 true?
Vadim26 [7]

Answer:

6.

Step-by-step explanation:

11 + 2k > 19

2k > 19 - 11

2k > 8

k > 8/2

k > 4.

4 0
3 years ago
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