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larisa86 [58]
4 years ago
14

What additional information is needed to prove that the triangles are congruent using the asa congruence theorem?nl ≅ mpnk ≅ mqn

≅ ml ≅ p
Mathematics
2 answers:
Ainat [17]4 years ago
5 0

Answer:

L ≅ P

Step-by-step explanation:

Mariulka [41]4 years ago
4 0
If two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. You can included how some sides or angles are congruent.
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Solve the system of equations using the substitution method (solving for x and y intercepts). Please give graphing points.
ch4aika [34]

Answer:

(x, y) = (1, 4)

Step-by-step explanation:

Given:  x+y=5 and 2x-y=-2

Solve for y and x

x+y=5; solve for y

y = 5 - x; substitute into other equation

2x-y= -2

2x - (5 - x) = -2

2x - 5 + x = -2; combine x's

3x - 5 = -2; add 5 to both sides

3x =3; divide by 3

x = 1; use this to solve for y

x+y=5

1 + y = 5; subtract 1 from both sides

y = 4

(x, y) = (1, 4)

4 0
3 years ago
Eight less than four times a number is less than 56. What are the possible values of that number?
zmey [24]

Answer:

hu

Step-by-step explanation:

j

3 0
3 years ago
Find the volume of the composite solid.
ioda
I hope this helped, have a nice day

6 0
3 years ago
Read 2 more answers
Eight rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other ro
Brums [2.3K]

Answer:

9.11*10^-4 %

Step-by-step explanation:

To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.

For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320

In order to find the total amount of ways to place the rooks, you can just use a combinatoric:

\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9

Then:

P = \frac{40320}{4.43*10^9}*100\%=9.11*10^{-4}\%

5 0
4 years ago
Select the correct answer.
miss Akunina [59]

Answer:

6211 c.u. ft.

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
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