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masya89 [10]
3 years ago
6

If I have $16.80 and magnets are .80 cent how many can I buy ?

Mathematics
1 answer:
vladimir2022 [97]3 years ago
3 0
He can buy at least 21 magnets
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How
andrey2020 [161]

Answer: 7800

Step-by-step explanation:

As English alphabet has 26 letters.

So , Choices for First character in the code = 26

The choices for digits = 10  (From 0 to 9)

So , choices for second character = 10  (Middle two characters must be numbers)

choices for third character = 10            (Middle two characters must be numbers)

Choices for last character = 3   (the  last character must be a 1, 3, or 7)

By Fundamental principle of counting , the total number of four character codes can be generated =

(Choices for First character)x (choices for digits) x(choices for digits) x(Choices for last character)

= (26) (10)(10)(3) =7800

Hence, the total number of character codes can be generated= 7800

6 0
3 years ago
Shannon sells handmade wallets for $12 each.
White raven [17]

Answer:

<h2>N=11</h2>

<h2>Step-by-step explanation:</h2><h2>So you do 396 divided by 12=33</h2><h2>she sold 3 more wallets so then u would do 33 divided by 3 which would equal = <u>11</u></h2>

7 0
3 years ago
????????????????vbzjjzjdvdu
Romashka-Z-Leto [24]

Answer:

A

Step-by-step explanation:

There is an empty dot on 4, meaning b is not equal to 4.

The arrow is going to the left of 4, so it means that b is less that four.

Hope that helps!

3 0
2 years ago
Read 2 more answers
Which pair of ratios form a proportion?
Roman55 [17]
Your answer is B::))


7 0
3 years ago
Read 2 more answers
How can help me with (c)
dimulka [17.4K]
X^2-y^3=6
x^2-6=y^3
y= (x^2-6)^1 by 3
6 0
3 years ago
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