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3 years ago

6

If I have $16.80 and magnets are .80 cent how many can I buy ?

1 answer:

vladimir2022 [97]3 years ago

3 0

He can buy at least 21 magnets

You might be interested in

Can someone pls help and pls dont get it wrong

STatiana [176]

Answer:

D

Step-by-step explanation:

The inverse property states that any number multiplied by its reciprocal equals 1.

7 0

3 years ago

Wich is the set i need u heeeeelp

Karo-lina-s [1.5K]

Answer:

I think that it is 26, 51, 103,

I hope this is correct sorry if I'm wrong

Step-by-step explanation:

you add all of them together and they have to get to 180 so 26+51=77 77+103=180

7 0

3 years ago

In the figure, point k is the image of point j under a reflection across line L. Find y

Viktor [21]

Since, <span>point K is the image of point J under a reflection across line L.

The distance, JM = MK

</span>Hence, 2x + 4 = 4x - 6
4x - 2x = 4 + 6
2x = 10
x = 5

Also refrection of a point across a line form an angle of 90 degrees at the point of refrection.
i.e. 3y - 30 = 90
3y = 90 + 30 = 120
y = 120 / 3 = 40

Therefore, the value of y is 40.

4 0

3 years ago

I really really need help!!!!!!

Svetllana [295]

ANSWER

$y = 5 \sin( \frac{6}{5} x - \pi)-4$

EXPLANATION

The given function is

$y = 5 \cos( \frac{3}{5} x - \pi) + 4$

The period of this function can be determined using the formula:

$T= \frac{2\pi}{ |b| }$

.

The period is

$T= \frac{2\pi}{ \frac{3}{5} } = \frac{10\pi}{3}$

Half the period of this function is:

$\frac{ \frac{10\pi}{3} }{2} = \frac{5\pi}{3}$

The function which has this period is

$y = 5 \sin( \frac{6}{5} x - \pi) -4$

The first choice is correct.

3 0

3 years ago

Which of the following inverse functions are defined for x = - 1/2? Select 4 of the following that apply. There must be 4 select

Finger [1]

Answer:

$y=cos^{-1}(x)$ ,

$y=cot^{-1}(-\frac{1}{2})$ ,

$y=sin^{-1}(-\frac{1}{2})$

$y=tan^{-1}(-\frac{1}{2})$

Above four functions are defined at the given point.

Step-by-step explanation:

We have been given all trigonometric function we need to tell which among them is defined for $x=-\frac{1}{2}$

Case 1: $y=cos^{-1}(x)$

Since, $At x=-\frac{1}{2}$

$y=cos^{-1}(-\frac{1}{2})$

$y=-cos^{-1}(\frac{1}{2})$

$y=\frac{2\pi}{3}$

Domain of the function is $[-1,1]$

Defined at given point.

Case 2: $y=cot^{-1}(-\frac{1}{2})$

$y=-cot^{-1}(\frac{1}{2})$

$y=-1.1071$

Domain of the function is $(-\infty,\infty)$

Defined at given point.

Case 3: $y=cosec^{-1}(-\frac{1}{2})$

$y=-cosec^{-1}(\frac{1}{2})$

Value of the function is not defined because it is out of the domain of the function.

Domain is $(-\infty,-1]\cup[1,\infty)$

So, not defined at given point.

Case 4: $y=sec^{-1}(-\frac{1}{2})$

$y=-sec^{-1}(\frac{1}{2})$

Value of the function is not defined because it is out of the domain of the function.

Domain is $(-\infty,-1]\cup[1,\infty)$

So, not defined at given point.

Case 5: $y=sin^{-1}(-\frac{1}{2})$

$y=-sin^{-1}(\frac{1}{2})$

$y=\frac{-\pi}{6}$

Domain of the function is $[-1,1]$

Defined at given point.

Case 6: $y=tan^{-1}(-\frac{1}{2})$

$y=-tan^{-1}(\frac{1}{2})$

$y=-0.4636$

Domain of the function is $(-\infty,\infty)$

Defined at given point.

Therefore, Option 1,2,5,6 are correct.

5 0

3 years ago

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