Step-by-step explanation:
A regular megagon is repr {1,000,000} and can be constructed as a truncated 500,000-gon, t{500,000}, a twice-truncated 250,000-gon, tt{250,000}, a thrice-truncated 125,000-gon, ttt{125,000}, or a four-fold-truncated 62,500-gon, tttt{62,500}, a five-fold-truncated 31,250-gon, ttttt{31,250}, or a six-fold-truncated 15,625-gon, tttttt{15,625}. A regular megagon has an interior angle of 179.99964°. The area of a regular megagon with sides of length a is given by
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Answer:
height of water in the container is 3 cm.
Step-by-step explanation:
Given;
A sealed rectangular container, measuring 4 cm by 8 cm by 16 cm
the height of the container is 16 cm, when filled with water at 4 cm level from the top, thus, the height of water in the container is (16 cm - 4cm) = 12cm
Volume of water in the container when it is sitting on its smallest face = 4 cm x 8 cm x 12 cm = 384 cm³
Volume of water in the container when it is sitting on its largest face = 8 cm x 16 cm x h
where;
h is height of water in the container
384 = 8 x 16 x h
384 = 128h
h = 384 / 128
h = 3 cm
Therefore, height of water in the container is 3 cm.
I believe that the answer is x>-1
The correct answer would be A. x=20/3 because it is proportional.<span />
F(x) = 10x + 20
y = 10x +20
I don’t know if you want an equation