(2^8 *3^-5* 6^0)^-2 * ((3^-2)/(2^3))^4 * 2^28
anything to the 0 power is 1
(2^8 *3^-5* 1)^-2 * ((3^-2)/(2^3))^4 * 2^28
using the power of power property to take the power inside
(2^(8*-2) *3^(-5* -2) * (3^-2*4)/(2^3*4) * 2^28
simplify
2^ -16 * 3^10 * 3^-8 /2*12 * 2^28
get rid of the division by making the exponent negative
2^-16 * 3^10 * 3^-8 *2*-12 * 2^28
combine exponents with like bases
2^(-16-12+28) * 3^(10-8)
2^(0) *3^2
anything to the 0 power is 1
1*9
9
Answer
63rrdddd
Step-by-step explanation:
Answer:
0.96153846153
but it would make more sense in a lot of cases if it was 5.2/5
Step-by-step:
The answer to this question would be true.
An odd number wouldn't have any 2 in their factor because it is the definition of odd number, can't be divided by 2. Since they have no probability of having factor 2, then their GCF would not become an even number.
110 that's the answer I think
