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Elis [28]
3 years ago
14

What is 8.275 rounded to the nearest hundred of an ounce?

Mathematics
2 answers:
Kay [80]3 years ago
8 0
8.275
8.28 is the estimated answer
lisabon 2012 [21]3 years ago
8 0
Hello there.
<span>
What is 8.275 rounded to the nearest hundred of an ounce?
</span>
8.28 
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Ted analyzes how much sugar is in 3 popular candy bars. He records the data on the line plot below.
Fiesta28 [93]

Answer: 81 1/2

to determine the total amount of sugar we need to add

21 1/2 + 30 +30

^add the whole numbers the. add the fractions (21 +30+30) + (1/2)<<<

=81 + 1/2

which is equal to

81 1/2

4 0
2 years ago
A dairy scientist is testing a new feed additive. She chooses 13 cows at random from a large population of cows. She randomly as
mina [271]

Answer:

Step-by-step explanation:

Given that a dairy scientist is testing a new feed additive. She chooses 13 cows at random from a large population of cows. She randomly assigns nold = 8 to get the old diet, and nnew = 5 to get the new diet including the additive.

From the data given we get the following

           N       Mean      StDev     SE Mean

Sample   1    8           43       5.1824 1.832

Sample   2   5           73     21.0832 9.429

df = 11

Std dev for difference = 13.3689

a) Yes the two are independent.  The two sets of cows randomly chosen are definitely independent. Paired means equal number should be there and homogeneous conditions should be maintained.

b) Enclosed

c) Comparison of two means is the test recommended here.  Because independent samples are used.\

d) Test statistic= -3.1233

(because of unequal variances we use that method)

95% confidence interval =  ( -56.6676 , -3.3324 )

p value <0.05 our alpha

So reject null hypothesis.

The two means are statistically significantly different.

3 0
3 years ago
What is 50 tens ×4 hundred = 40 tens × 5hundred true or false?
Vladimir79 [104]
True. 500x400=400x500
3 0
3 years ago
Given sinθ=- 3/5 and cscθ=-5/3 in quadrant III, find the value of other trigonometric functions using a Pythagorean Identity. Sh
Yakvenalex [24]
Let ABC be a triangle in the 3rd quadrant, right-angled at B. 
 So, AB-> Perpendicular BC -> Base AC -> Hypotenuse. 
Given: sinθ=-3/5 cosecθ=-5/3 
 According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
 Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
 Since sinθ=Perpendicular/Hypotenuse ,
 AC=5 and AB=3
 Substituting these values in equation (1)
 
〖BC〗^2=〖AC〗^2-〖AB〗^2

 ă€–BC〗^2=5^2-3^2
 

 ă€–BC〗^2=25-9

 ă€–BC〗^2=16

 BC=4 units

 Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
 So,cosθ=Base/Hypotenuse Cosθ=-4/5 
 secθ=Hypotnuse/Base secθ=-5/4 
 tanθ=Perpendicular/Base tanθ=3/4  
 cotθ=Base/Perpendicular cotθ=4/3
4 0
2 years ago
I need clean and clear answers please!<br><br> Thank you
lina2011 [118]
Okay so we get: subtract m + 8 from 5m + 11

5m + 11 = 16 + m or 16m

16m - 8 +m or 8m = 8m or 8 + m

5 0
2 years ago
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