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dolphi86 [110]
3 years ago
5

How do you write 1% as a fraction in simplest form

Mathematics
2 answers:
ycow [4]3 years ago
7 0
1/100 bc the persentage is to 100% and you have 1% makes sence
makkiz [27]3 years ago
5 0
1/100 This is because every percent is out of 100.

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Solve for x. 8(9x-4)-2=3+2
gavmur [86]
So first you have to move the -2 over to the opposite side.
8(9x-4)=3+2+2
Then you can simplify the right side 
8(9x-4)=7
Then you distribute
8*9x=72x
8*-4=-32
so now you have...
72x-32=7
Then you move the 37 over
72x=39
Then you divide by 72 to isolate x
x=39/72 or x= 13/24 or <span>x=0.54167</span>
6 0
3 years ago
What is the least common multiple of 2x^2 and 4x+12
Shalnov [3]

Answer:

4 x ^2 ( x + 3 )

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

4 0
3 years ago
Suppose f(x) = x2 and g(x) = (3x)2. Which statement best compares the graph
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  f(x) = x^2 and g(x) = (3x)^2.

g(x) can be rewritten as 9x^2.

The graph of g(x) is only one ninth as wide as that of f(x).

Next time please share the possible answer choices.  Thank you.

6 0
3 years ago
Find the standard deviation for the set of data.<br> {5,4, 18, 14, 22, 20, 6, 16, 12}
ira [324]
The Answer is 6.3245553203368.

Also if you can please answer my recent question.
That will Mean so much.
6 0
2 years ago
The mean preparation fee H&amp;R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
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