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allochka39001 [22]

2 years ago

14

80% of the students in 4-6 building at LVA are virtual.If we have 1200 students TOTAL in the 4-6 building, how many students are

virtual?

1 answer:

wariber [46]2 years ago

7 0

960 students are virtual !

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Can sum help me?? will get brainlistt

raketka [301]

Answer:

C. Logan

Step-by-step explanation:

you divide the amount of problems by how many minutes it took each person. for example if you divide the amount of problems Logan did by how many minutes it took him. (84÷3) it equals 28.

7 0

3 years ago

Of the 80 boys polled at lunch, 55% say they play video games daily. According to the poll, how many boys play video games daily

alexdok [17]

$55% = \frac{55}{100} = \frac{11}{20}$

Multiply $\frac{11}{20}$ by 80 and you will get how many boys play video games daily.

$\frac{11}{20}*80=\frac{11}{1}*4=11*4=44$

44 is the number of boys who play video games daily.

8 0

3 years ago

The quadratic function g(x) = a.ca + bx+c has the

Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

$f(x)=ax^2+bx+c$

Here we know that the leading coefficient $a=1$ so we reduce our equation to:

$g(x)=x^2+bx+c$

The roots are those values at which $g(x)=0$

So:

$x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\ 49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\$

$Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\ 49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0$

So we have:

$(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}$

Finding c from (1):

$33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}$

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0

3 years ago

Please show me what formula to use to solve equation <br> x2-6x=13

makvit [3.9K]

X^2-6x=13
(x-3)^2-9=13
(x-3)^2=22
(x-3)= +-sqrt22
x = sqrt22+3 or x = -sqrt22+3

3 0

3 years ago

A farmer needs 3x2 − 4x + 10 seeds for each of x3 + 5x − 20 fields. What expression would represent the seeds the farmer needs t

Fittoniya [83]

Answer:

Step-by-step explanation:

(3x^2-4x+10)(x^3+5x-20) = $3x^5-4x^4+25x^3-80x^2+130x-200$

x=1 is not a good value since when you plug it in you get -126 and you can't have a negative number of seeds.

7 0

3 years ago