Answer:
Standard form is another way to write slope-intercept form (as opposed to y=mx+b). It is written as Ax+By=C. You can also change slope-intercept form to standard form like this: Y=-3/2x+3. Next, you isolate the y-intercept(in this case it is 3) like this: Add 3/2x to each side of the equation to get this: 3/2x+y=3.
Step-by-step explanation:
Standard form is another way to write slope-intercept form (as opposed to y=mx+b). It is written as Ax+By=C. You can also change slope-intercept form to standard form like this: Y=-3/2x+3. Next, you isolate the y-intercept(in this case it is 3) like this: Add 3/2x to each side of the equation to get this: 3/2x+y=3.
Answer:
Option C. −4≤t≤−3
Step-by-step explanation:
we have
This is the equation of a vertical parabola written in vertex form
The parabola open upward (the leading coefficient is positive)
The vertex is a minimum
The vertex is the point (-3,5)
The function is increasing in the interval [-3,∞)
The function is decreasing in the interval (-∞,-3]
The function will have a negative average rate when the function will be decreasing
therefore
the answer is option C
To write this function in function notation all you would need to do is rearrange the equation for y.
3x + 2y = 12
3x - 3x + 2y = 12 - 3x
2y = 12 - 3x
2y/2 = 12/2 - 3x/2
Y = 6 - 3/2 X or
Y = -3/2 X + 6.
You can pick any of them it won’t hold it against you.
I do it all the time.
Have a good day
