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Grace [21]
3 years ago
5

9 = x/2 + 2 solve for x.

Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0

Answer:

14 = x

Step-by-step explanation:

-2 on both sides you get 7 = x/2, multiply both sides by 2 and you get 14 = x

Temka [501]3 years ago
5 0

Answer:

x= 14

Step-by-step explanation:

First, lets take the L.C.M on one side, so that it becomes a little more unified.

=> 9= X/2 + 4/2

now, lets shift the 2 to the L.H.S to make it even simpler.

=> 18= x+4

Now, lets move 4 to the L.H.S, to subtract it from 18.

=> 14= x

Thus, x=14

:)

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There are 36 bikes in a store (18 pairs). 1 pair(s) are yellow, 3 pairs are red, and the rest are purple. If you took out a purp
LenaWriter [7]

Answer: 27/36

Step-by-step explanation: It says there are 36 bikes (18 pairs), meaning that there are 2 bikes per pair because 18 multiplied by 2 is 36.

1 pair (2 bikes) are yellow.

3 pairs (6 bikes) are red.

For purple, add yellow and red together: 2 + 6 = 8. Subtract the total number of bikes from this: 36 - 8 = 28 purple bikes.

If you take out 1 purple bike, this leaves you with 27. The probability of choosing a purple bike out of the total (36), is 27/36.

Please let me know if this is correct or wrong.

8 0
3 years ago
Hayden wanted to investigate whether there was a difference in the time spent in the checkout line between two grocery stores. S
Ber [7]

Answer:

No.  The data in this study were not based on a random method.  This is a key requirement for an inference to be made from the two-sample t-test.

Step-by-step explanation:

1. Hayden can use the two-sample t-test (also known as the independent samples t-test)to find out if there was a difference in the time spent in the checkout time between two grocery stores and to conclude whether the difference in the average checkout time between the two stores is really significant or if the difference is due to a random chance.  There are three conditions to be met when using the two-sample t-test.

2. The first condition is that the sampling method must be random.  This requirement was not met in this study.  Each customer from each store should have an equal chance of being selected for the study.  This was not achieved.

3. The distributions of the sample data are approximately normal.  This is achieved with a large sample size of 30 customers selected for each study.

4. The last but not the least condition is the independence of the sample data.  Sample data here is independent for both samples.

5 0
3 years ago
Evaluate 33/5 - 1/10
azamat

Answer:

\large\boxed{\dfrac{13}{2}=6\dfrac{1}{2}=6.5}

Step-by-step explanation:

We have the different denominators.

The common denominator is 10.

\dfrac{33}{5}=\dfrac{33\cdot2}{5\cdot2}=\dfrac{66}{10}

We can subtract these fractions now.

\dfrac{33}{5}-\dfrac{1}{10}=\dfrac{66}{10}-\dfrac{1}{10}=\dfrac{66-1}{10}=\dfrac{65:5}{10:5}=\dfrac{13}{2}\\\\\dfrac{13}{2}=\dfrac{12+1}{2}=6\dfrac{1}{2}

3 0
3 years ago
Read 2 more answers
HOW DO I SOLVE THIS FAST I NEED TO KNOW ASAP
artcher [175]

Answer:

Solve what? lol

8 0
3 years ago
The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?
adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)

\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t  \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}

$$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$$

3 0
2 years ago
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