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zhenek [66]
3 years ago
11

The value of 4 less than the product of 0.25 and x is greater than 6. What are all the possible values of x? SHOW YOUR WORK!

Mathematics
1 answer:
seraphim [82]3 years ago
6 0

Answer:

0.25x - 4 > 6

Step-by-step explanation:

First, we would like to thank you for all of the additional support you offer at home. ... Subtract the absolute values. Multiply the denominators. 4. Reduce if necessary. 3. 10 x. 2. 3. 6. 30. = 1. 5. 3 ... 1 less than the product of 3 and m 3m – 1.

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Verdich [7]

Answer:

Of which question?????

5 0
2 years ago
Read 2 more answers
The 759 students in Chad's middle school.44% participate in sports, 29% play in the band,
stellarik [79]

Answer:

A - 220

B -  205

Step-by-step explanation:

29% of 759 is 220.11, round down so it stays 220.

27% of 759 is 204.93 round up so it becomes 205.

bonus:

44% of 759 is 333.96 round up and it becomes 334.

to check your work, add 220, 205, and 334 and its 759. thats how you can be sure its correct.

hope this helps :)

3 0
2 years ago
Write each polynomial in standard form. Then state the degree, the number of terms, and
salantis [7]
Standard form:
-4x^3 - 6x^2 + 2x + 12

Degree = 3

Terms = 4

Zeros = 3
8 0
2 years ago
The population of a town in 2007 is 113, 505
ELEN [110]

from 2007 to 2012 is only 5 years, so we can see this as a compound interest with a rate of 1.2% per annum for 5 years, so

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$113505\\ r=rate\to 1.2\%\to \frac{1.2}{100}\dotfill &0.012\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=113505\left(1+\frac{0.012}{1}\right)^{1\cdot 5}\implies A=113505(1.012)^5\implies A\approx 120481

7 0
1 year ago
The answer to this question asap please
Mkey [24]

At 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the​ state's eighth graders on this exam is more than 280.

<h3>How to state hypothesis conclusion?</h3>

We are given;

Sample size; n = 78

population standard deviation σ = 37

Sample Mean; x' = 280

Population mean; μ = 287

The school administrator declares that mean score is more (bigger than) 280. Thus, the hypotheses is stated as;

Null hypothesis; H₀: μ > 280

Alternative hypothesis; Hₐ: μ < 280

This is a one tail test with significance level of α  = 0.13

From online tables, the critical value at α  = 0.13 is z(c) = -1.13

b) Formula for the test statistic is;

z = (x-  μ)/(σ/√n)

z = ((280 - 287) *√78 )/37

z = -1.67

c) From online p-value from z-score calculator, we have;

P[ z > 280 ] =  0.048

d) The value for z = -1.67  is smaller than the critical value mentioned in problem statement z(c) = - 1.13  , the z(s) is in the rejection zone. Therefore we reject H₀

e) We conclude that at 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the​ state's eighth graders on this exam is more than 280.

Read more about Hypothesis Conclusion at; brainly.com/question/15980493

#SPJ1

5 0
1 year ago
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