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Ghella [55]
3 years ago
10

Find the area of the figure below.

Mathematics
2 answers:
laiz [17]3 years ago
5 0

Answer:

42 in.²

Step-by-step explanation:

We need to find the area of the rectangle and then the triangle and then add them up. For the rectangle its 6 x 5 = 30 and for the triangle its 6 x 4 = 24/2 = 12 *we have to divide by 2 because we are finding the area of a triangle*. So we add 30 + 12 = 42 so your answer is 42 in.²

:DDD hope I was able to help

Fudgin [204]3 years ago
3 0

Answer:

Area = 42 in^2

Step-by-step explanation:

here's your solution

=> divide above picture in two parts

=> rectangle and traingle

=> area of rectangle = length* width

=> area of rectangle = (5*6)in.

=> area of rectangle = 30 in^2

=> now, area of traingle = 1/2*base *height

=> area of traingle = 1/2*4*6

=> area of traingle = 12 in^2

=> area of figure = 30 in^2 + 12 in^2

=> Area = 42 in^2

hope it helps

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1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that \mu = 6.6, \sigma = 1.1

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

Z = \frac{X - \mu}{\sigma}

-2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = -2.41*1.1

X = 3.95

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

Z = \frac{X - \mu}{\sigma}

2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = 2.41*1.1

X = 9.25

The maximum head breadth that will fit the clientele is of 9.25-in.

8 0
2 years ago
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