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cestrela7 [59]
3 years ago
12

HELP ASAP WILL GIVE BRAINLIEST!! Write the equation in point-slope form for the line that contains the points

Mathematics
1 answer:
Umnica [9.8K]3 years ago
6 0
Using y=mx+b

Slope-intercept form:

y=x-1

Point-slope form:

Y+3=1(x+2)
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If a box is 12.2 cm by 9.8 cm by 16.4 cm, what is the volume of the box?
sp2606 [1]
To find volume multiply length, width, and height.
12.2 x 9.8 x 16.4 =1960.784
The answer is 1960.748 cm.
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3 years ago
Create equations to solve for missing angles may be hard for me to solve. Need help on this!!​
Sonja [21]

Answer: A.2x+30=90

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5 0
3 years ago
one x-intercept for a parabola is at the point (2, 0). use the quadratic formula to find the other x-intercept for the parabola
omeli [17]

Answer:

Step-by-step explanation:

There are 3 ways to find the other x intercept.

1) Polynomial Long Division.

Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.

2) Just solving for x when y = 0, by using the quadratic formula.

x^2 - 3x + 2 = 0\\x_{12} = \frac{3 \pm \sqrt{9 - 4(1)(2)}}{2} = \frac{3 \pm 1}{2} = 2, 1.

So the other x - intercept is at (1, 0)

3) Using Vietta's Theorem regarding the solutions of a quadratic

Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.

x_1 + x_2 = \frac{-b}{a}

And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.

x_1 \cdot x_2 = \frac{c}{a}

These relations between the solutions give us a brief idea of what the solutions should be like.

6 0
3 years ago
Somebody pls help me and pls show work!<br> (no links)
miss Akunina [59]

Answer:

I think the answer is letter A.

8 0
3 years ago
Read 2 more answers
Is the given function phi(x) = x^2 - x^-1 an explicit solution to the linear equation d^2y/dx^2 - 2/x^2 y = 0? Circle your answe
mart [117]

Answer:

Yes

Step-by-step explanation:

We are given that a function \phi(x)=x^2-x^{-1}

We have to find that given function is an explicit solution to the linear equation

\frac{d^2y}{dx^2}-\frac{2}{x^2}y=0

If given function is an explicit solution of given linear equation then it satisfied the given differential equation

Differentiate w.r.t x

Then we get \phi'(x)=2x+x^{-2}

Again differentiate w.r.t x

Then we get

\phi''(x)=2-\frac{2}{x^3}

Substitute all values in the given differential equation

2-\frac{2}{x^3}-\frac{2}{x^2}(x^2-x^{-1})

=2-\frac{2}{x^3}-2+\frac{2}{x^3}=0

Hence, given function is an explicit solution of given differential equation.

Therefore, answer is yes.

3 0
3 years ago
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