Find b and s. At The present time Mrs. B's age is six years more than four times her sons age. Three years ago she was seven tim
1 answer:
Answer:
Mrs. B's age = y = 38 years
her son's age = x = 8 years
Step-by-step explanation:
To Find:
Mrs. B's age = y =?
her son's age = x = ?
Solution:
Let Mrs. B's age be 'y' years
and her son's age be 'x' years
Three years ago Mrs B's will be (y - 3) and her son's age will be (x - 3)
According to the first given condition,
y = 6 + 4x ...............Equation ( 1 )
According to the second given condition,
(y - 3 ) = 7 (x - 3 )..........Equation ( 2 )
equating equation 1 in equation 2 we get
6 + 4x -3 = 7x - 21
7x - 4x = 21 + 3
∴
Now substitute x in equation 1 we get
y = 6 + 4×8
y = 6 + 32
∴ y = 38 years
Mrs. B's age = y = 38 years
her son's age = x = 8 years
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