Answer:
10 miles per 1 minute
Step-by-step explanation:
100 miles / 10 minutes
100/10
10/1
10 miles / 1 minute
Answer:
θ ≈ 36.03°
Step-by-step explanation:
We can use tangent (opposite side / adjacent side) for this question:
tan (θ) = 8 / 11
θ = tan⁻¹ (8/11)
θ = 36.02737339
θ ≈ 36.03°
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Tree...........................dock
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boat
use Pythagorean Theorem to satisfy...a^2 + b^2 = c^2
200^2 + b^2 = 300^2
b^2 = 300^2 - 200^2
b^2 = 50000 (get square root of each)
b = 223.606 (rounded to the nearest tenth.... = 223.6