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3 years ago

Please help!!!

1 answer:

7 0

The answer is: The first box.
The explanation is shown below:
1. You must apply the formula for calculate the area of regular pyramid, which is:
A=Base area+(PerimeterxSlant height)/2
2. The area of the first box is:
Slant heigth=√(45 cm)²+(15 cm)²
Slant height=47.43
A1=(30 cm)²+(30 cmx4)(47.43 cm)/2
A1=3745.8 cm²
2. The area of the second box is:
Slant heigth=√(35 cm)²+(10 cm)²
Slant height=36.40 cm
Base area=(10 cmx7.5 cm/2)16
Base area=600 cm²
A2=600 cm²+(120 cm)(36.40 cm)/2
A2=2784 cm²
3. Therefore A1>A2

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3 years ago

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(6+3)÷(4-5)Evaluate the following numerical expressions.

AlexFokin [52]

Answer: -9

Step-by-step explanation:

(6+3)÷(4-5)

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3 years ago

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago