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SCORPION-xisa [38]
3 years ago
10

A 2 by 3 rectangle contains 8 squares. A 3 by 4 rectangle contains 20 squares. A 4 by 6 rectangle contains 50 squares. What size

rectangle contains exactly 100 squares? Is there more than one? Can you find them all? Can you prove there are no more?

Mathematics
1 answer:
scZoUnD [109]3 years ago
4 0

Answer:

The rectangles that have exactly 100 squares are 1 by 100  4 by 11 and 5 by 8

Step-by-step explanation:

The given parameters are;

A 2 by 3 rectangle contains 8 squares

A 3 by 4 rectangle contains 20 squares

A 4 by 6 rectangle contains 50 squares  

We note that the number of squares varies proportionately to the increase in the dimension of the rectangle, that is we have;

2 by  3 rectangle contains 8 squares

3 by 4 rectangle contains 20 squares increase by 12 = 3 × 4

4 by 5 rectangle contains 40 squares increase by 20 = 4 × 5

The number of squares formed can therefore be arranged in a matrix as follows(please see attached matrix);

Column,     1,       2,     3,      4,       5,     6,        7,       8,         9,           10,         11

Row

1

2

3

4

5

6

7

8

9

10

11

It will be observed that after reaching a point where the row and column are equal, (x, x) the rate of increase in the number of squares become constant and equal to x × ((x - 1) × 0.5) + 1) = x × (x + 1)/2

From the matrix, the rectangles that have exactly 100 squares are 1 by 100  4 by 11 and 5 by 8 and there are no more as presented in the attached matrix, the number of squares formed keeps increasing for each column and row added.

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Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let \mu denotes the average hours of sleep per night.

As per given , we have

H_0:\mu=7\\H_a:\mu

, since H_a is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : \overline{x}=7.24

Sample  standard deviation : s= 1.93

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e.  t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58

For significance level \alpha=0.05 and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= t_{\alpha, df}=t_{0.05,21}=- 1.7207

Decision : Since the test statistic value (0.58) > critical value  1.7207, it means we are failed to reject the null hypothesis .

[Note : When |t_{cal}|>|t_{cri}|, then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

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3 years ago
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Answer:

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Step-by-step explanation:

Step 1: Simplify both sides of the equation.

Step 2: Flip the equation.

Step 3: Add 5 to both sides.

Step 4: Multiply both sides by 4/(-1).

g=−32

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3 years ago
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Answer:

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In order to find the answer, you would need to add $23.66 plus $6.65.

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